<h2>
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>you</u><u> </u><u>❣❣</u><u> </u></h2>
<h2>
<em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em></h2>
<em><u>in</u></em><em><u> </u></em><em><u>fraction</u></em><em><u>=</u></em><em><u>29</u></em><em><u>/</u></em><em><u>15</u></em><em><u>0</u></em>
Answer:
2. can not be 3 bc it would 5
Step-by-step explanation:
Answer:
2. n = 11
4. g = -2
6. t = 21
8. n = 4
10. y = -1
Step-by-step explanation:
2. 63 = -3(1 - 2n)
Dividing both the side by negative 3 we get
4. -g + 2(3 + g) = -4(g + 1)
First we will open the bracket by distributive property A( B +C) = AB + AC
6.-3(t +5 ) + (4t + 2) = 8
Using distributive property A( B +C) = AB + AC we get
8. -8 - n = -3(2n -4)
Using distributive property A( B +C) = AB + AC we get
10. -4( 2 - y) + 3y = 3(y - 4)
Using distributive property A( B +C) = AB + AC we get
I would think you would use 1/3 of a cup but I am not sure.Hope it helps!
Okay, here we have this:
Considering the provided information, we are going to calculate the requested probability, so we obtain the following:
So to calculate the probability of the conjunction of two events we will substitute in the following formula:
Replacing:
P(wearing brown shoes or tennis shoes U sneakers)=(30+58-8)/100
P(wearing brown shoes or tennis shoes U sneakers)=80/100
P(wearing brown shoes or tennis shoes U sneakers)=0.8
Finally we obtain that the probability that a randomly selected teacher is wearing brown shoes or tennis shoes/sneakers is 0.80.