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3 years ago

Please help me out :)

Mathematics

1 answer:

svetoff [14.1K]3 years ago

3 0

Answer:

818.4 in²

Step-by-step explanation:

shaded region = area of sector - area of triangle

area of sector = area of circle × fraction of circle

A = π × 27.8² × $\frac{150}{360}$ ≈ 1011.65 in²

area of triangle = 0.5 × 27.8 × 27.8 × sin150° ≈ 193.21 in²

shaded region = 1011.65 - 193.21 ≈ 818.4 in²

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What is the answer too 4(2x+1)

Archy [21]

Answer:

8x+4

Step-by-step explanation:

4(2x+1)=8x+4

8 0

3 years ago

Read 2 more answers

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

The incomplete work of a student to solve an equation is shown below:

Dvinal [7]

Answer: 4x = -8

Reasoning:
Multiply both sides by 4

7 0

3 years ago

What property is -7 + 8 minus + 2

Fofino [41]

I believe its additive Inverse Property

8 0

3 years ago

A 165 inch pipe is cut into two pieces. One piece is four times the length of the other.Find the length of the shorter piece. Ho

coldgirl [10]

Answer:

Length of longer length=132 inches

Length of shorter length=33 inches

Step-by-step explanation:

Step 1: Determine total length of pipe

Total length of pipe=165 inches

Step 2: Derive expression for all the lengths

We can express all these lengths as follows;

L=l1+l2

where;

L=total length

l1=length of longer piece

l2=length of shorter piece

but;

length of longer piece=4×length of shorter piece

replacing;

l1=4l2

replacing;

L=165

l1=4×l2

165=l 2+4 l2

5 l2=165

l2=165/5

l2=33 inches

l1=length of longer length=33×4=132 inches

l2=length of shorter length=33 inches

4 0

3 years ago