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joja [24]
4 years ago
10

I need help on this one please

Mathematics
1 answer:
Advocard [28]4 years ago
7 0
1 lemon costs 20p and 1 orange costs 45p so an orange costs 25p more
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What are all these . Please help I will mark Brainly
disa [49]

Answer:

for a the answer is 5 for b also 5 (the solution is also the same but the = sign will be >) and for c is true

Step-by-step explanation:

for a so its 2x=10 you divide it like this

<h3><u>2x</u>=<u>10</u></h3><h3>2    2 so the answer will be</h3><h3>x=5 so you mark 5</h3>
3 0
3 years ago
Complete the function table for the function: y=4x+4<br> х<br> у<br> -6<br> -1<br> 2<br> 8
Shalnov [3]

Answer:

-6,-1

Step-by-step explanation:

y=4x+4 then simplify and came up with -6,-1.

3 0
3 years ago
There are 50 students in a calculus class. The amount of time needed for the instructor to grade a randomly chosen midterm exam
natta225 [31]

Answer:

14.46% probability that the instructor can finish grading in 4 and a half hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of n values from a distribution, the mean is n\mu and the standard deviation is s = \sqrt{n}\sigma

In this problem, we have that:

\mu = 6*50 = 300, s = \sqrt{50}*4 = 28.2843

What is the probability that the instructor can finish grading in 4 and a half hours

Four and half hours is 4.5*60 = 270.

So this probability is the pvalue of Z when X = 270.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{270 - 300}{28.2843}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

14.46% probability that the instructor can finish grading in 4 and a half hours

8 0
3 years ago
Thea scored an average of 13 points per game in her first 5 basketball games. In her 6th game, the average changed to 17 points
sammy [17]
Average of 5 games = 13
Total of 5 games = 13 x 5 = 65

Average of 6 games = 17
Total of 6 games = 102

6th game = 102 - 65 = 37

---------------------------------------------------------------------
Answer: Her score for the 6th game as 37.
---------------------------------------------------------------------
6 0
3 years ago
What is 0.77 km in mm
Taya2010 [7]
770000 this is the answer i just researched it
3 0
4 years ago
Read 2 more answers
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