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ivolga24 [154]
3 years ago
11

What is the sixth term in the binomial expression (5y+3)^10

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0
330 would be the 6th term of the sequence
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Mr.banks left work at 5:15p.m it took him 1 1/4 hours to drive home.at what time did me.banks arrive home?
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6 hours and 40 mins which would be 6:45
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AlladinOne [14]

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Step-by-step explanation:

is this a test?

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Can someone solve these for me?
trapecia [35]

Answer:

In order of pictures,

Picture #1: 230

Picture #2: 140

Picture #3: 9.9

Picture #4: 13.5

Picture #5: 7.07

Step-by-step explanation:

I am not entirely sure that 3 - 5 are correct, but I know that 1 and 2 are correct. I am sorry if they are incorrect.

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4 0
3 years ago
What are two pair fractions with common denominators for 3/5 and 3/4
diamong [38]
The cheap answer is, you simply "grab the denominator of one and multiply it times the other's top and bottom", so let's do so,

\bf \cfrac{3}{5}\cdot \cfrac{4}{4}\implies \cfrac{12}{20}\qquad \qquad \qquad \qquad \qquad \cfrac{3}{4}\cdot \cfrac{5}{5}\implies \cfrac{15}{20}
6 0
3 years ago
These roots of the polynomial equation x^4-4x^3-2x^2+12x+9=0 are 3,-1,-1. Explain why the fourth root must be a real number. Fin
Alex787 [66]

Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.

Because we know 3 and -1 (multiplicity 2) are both roots, the last root r is such that we can write

x^4-4x^3-2x^2+12x+9=(x-3)(x+1)^2(x-r)

There are a few ways we can go about finding r, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be (-3)(1)(1)(-r)=3r.

Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

3r=9\implies r=3

so the missing root is 3.

Other things we could have tried that spring to mind:

- three rounds of division, dividing the quartic polynomial by (x-3), then by (x+1) twice, and noting that the remainder upon each division should be 0

- rational root theorem

4 0
3 years ago
Read 2 more answers
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