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topjm [15]
4 years ago
15

Jane buys \dfrac73 \text { yard} 3 7 ​ yardstart fraction, 7, divided by, 3, end fraction, start text, space, y, a, r, d, end te

xt of fabric to make a cat bed. She starts the project by cutting 4 \text { feet}4 feet4, start text, space, f, e, e, t, end text of fabric off the end. How many feet long is the remaining piece of fabric?
Mathematics
1 answer:
Vadim26 [7]4 years ago
6 0

The correct question is:

Jane buys 7/3 yards of fabric to make a cat bed. She starts the project by cutting 4 feet of fabric off the end. How many feet long is the remaining piece of fabric?

Answer:

There are 3 feet remaining.

Step-by-step explanation:

Jane cuts 4 feet from 7/3 yards, to know how many feet long yard is remaining, first we need to know how many feet make a yard, convert 7/3 yards to feet, and find the difference between the feet cut and the total feet available.

3 feet = 1 yard

x feet = 7/3 yards

3 × 7/3 = x × 1

x = 7

Therefore, 7 feet is 7/3 yards.

Now, she cuts 4 feet, do we have

(7 - 4 = 3) feet remaining.

Therefore, there are 3 feet remaining.

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Can someone help me please? the last point of the first graph ends on 6 ​
just olya [345]

Answer:

a) Yes

b) for reference, draw the line y = x, and reflect it over that, this reflection will be your inverse. Or switch the x and y values of each point of the function.

Here is a photo of the original function in black, it's inverse in red, and the line of reflection y = x in blue:

c) No, because it fails the vertical line test, when you draw a vertical line across the inverse function, it hits it more than once.

d) Domain of the original function: -6 ≤ x ≤ 6 ; x(the domain) is greater than or equal to -6 and less than or equal to 6.

e) Domain of inverse function: 0 ≤ x ≤ 4 ; x(the domain) is greater than or equal to 0 and less than or equal to 4.

f) Range of the original function: 0 ≤ y ≤ 4 ; y(the range) is greater than or equal to 0 and less than or equal to 4.

e2) Range of the inverse function: -6 ≤ y ≤ 6 ; y(the range) is greater than or equal to -6 and less than or equal to 6.

f2) x-intercept of original function: -6

g) y-intercept of the inverse function: -6

h) x-intercept of the inverse function: 4

i) y-intercept of the original function: 4

j) (2,2) or any point where the x, and y are the same within the function, or the point where the function intersects y = x.

5 0
3 years ago
Solve the quadratic equation 2x^2 + 6 = 8x by graphing.
Semmy [17]

Answer:

D is the right ans after solving eqn we get two value of x and they are 1 and 3

3 0
2 years ago
I can't remember for the life of me what these are
saw5 [17]

Answer:

same

Step-by-step explanation:

8 0
3 years ago
Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro
puteri [66]

Answer:

(a) P(0 ≤ Z ≤ 2.87)=0.498

(b) P(0 ≤ Z ≤ 2)=0.477

(c) P(−2.20 ≤ Z ≤ 0)=0.486

(d) P(−2.20 ≤ Z ≤ 2.20)=0.972

(e) P(Z ≤ 1.01)=0.844

(f) P(−1.95 ≤ Z)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)=0.862

(h) P(1.01 ≤ Z ≤ 2.50)=0.150

(i) P(1.20 ≤ Z)=0.115

(j) P(|Z| ≤ 2.50)=0.988

Step-by-step explanation:

(a) P(0 ≤ Z ≤ 2.87)

In this case, this is equal to the difference between P(z<2.87) and P(z<0). The last term is substracting because is the area under the curve that is included in P(z<2.87) but does not correspond because the other condition is that z>0.

P(0 \leq z \leq 2.87)= P(z

(b) P(0 ≤ Z ≤ 2)

This is the same case as point a.

P(0 \leq z \leq 2)= P(z

(c) P(−2.20 ≤ Z ≤ 0)

This is the same case as point a.

P(-2.2 \leq z \leq 0)= P(z

(d) P(−2.20 ≤ Z ≤ 2.20)

This is the same case as point a.

P(-2.2 \leq z \leq 2.2)= P(z

(e) P(Z ≤ 1.01)

This can be calculated simply as the area under the curve for z from -infinity to z=1.01.

P(z\leq1.01)=0.844

(f) P(−1.95 ≤ Z)

This is best expressed as P(z≥-1.95), and is calculated as the area under the curve that goes from z=-1.95 to infininity.

It also can be calculated, thanks to the symmetry in z=0 of the standard normal distribution, as P(z≥-1.95)=P(z≤1.95).

P(z\geq -1.95)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)

This is the same case as point a.

P(-1.20 \leq z \leq 2.00)= P(z

(h) P(1.01 ≤ Z ≤ 2.50)

This is the same case as point a.

P(1.01 \leq z \leq 2.50)= P(z

(i) P(1.20 ≤ Z)

This is the same case as point f.

P(z\geq 1.20)=0.115

(j) P(|Z| ≤ 2.50)

In this case, the z is expressed in absolute value. If z is positive, it has to be under 2.5. If z is negative, it means it has to be over -2.5. So this probability is translated to P|Z| < 2.50)=P(-2.5<z<2.5) and then solved from there like in point a.

P(|z|

7 0
3 years ago
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ololo11 [35]

Answer:

a=216

Step-by-step explanation:

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