The length of extra cable that is required to connect the two pieces of existing cable is equal to 182 meters.
<h3>How to determine the length of extra cable?</h3>
In order to determine the length of extra cable that is required to connect the two pieces of existing cable, we would apply the law of cosine as follows:
B² = A² + C² - 2(A)(C)cosB
Substituting the given parameters into the formula, we have;
B² = 325.0² + 430.0² - 2(325.0)(430.0)cos23
B² = 105,625 + 184,900 - 279,500(0.9205)
B² = 290,525 - 257,279.75
B² = 33,245.25
B = √33,245.25
B = 182.33 ≈ 182 meters.
Read more on cosine law here: brainly.com/question/11000638
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Answer:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
Answer:
What is Jeremy’s average if he received a total of 323.7 points on 7 tests?
Step-by-step explanation:
You have to divide 323.7 points by 7 tests so it is the only division problem out of all the problems.
Answer:
ok so anything raised to the power 0 is equal to 1 so we'll take 9x^0 =1 and then let's solve
Step-by-step explanation:
3x^2(9x)^0
3x^2(1)
=3x^2
