Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
Answer:
22w - 18
Step-by-step explanation:
To find the perimeter we have to add up all the sides
10w-10+w+1+10w-10+w+1
combine light terms
22w - 18 would be our answer
C because you got to find the like term term
Answer:
f(-2)=2
Step-by-step explanation:
f(-2)=4x+10
f=(4)(-2)+10
f=-8+10
f=2
Answer:
The two integers you are finding is 21 and 23.
x² + y² = 970
970 / 2 = 485 ( divide it to two because we are finding two integers )
√ 485 = 22.022715546 or when rounded off, 22 ( square root because we are finding squares )
It means, the answers are near the number 22.
I found out 21 and 23
21 and 23 is two consecutive odd integers
Let x = 21
Let y = 23
x² + y² = 970
( 21 )² + ( 23 )² = 970
= 441 + 529
= 970
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