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Stolb23 [73]
3 years ago
7

Which expression shows the distance on the number line between -7 and 16

Mathematics
2 answers:
Ghella [55]3 years ago
8 0

The expression for the distance of these two number on the number line is the absolute value of their difference:

|16-(-7)|=|23|=23

masha68 [24]3 years ago
5 0
-7 is less than 16 because -7 goes behind 0 and 6 is a positive number
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What is the domain of the function y=2 x-5?<br> O x&gt;-5<br> O x&gt;2<br> O x&gt;5<br> O x&gt;10
antiseptic1488 [7]
That’s a good one Because what is the domain of the function Y equals 2X
3 0
3 years ago
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
2 years ago
Can someone help me lol​
Ivenika [448]
Answer: 51
80+49=129
180-129= 51
4 0
2 years ago
A coat that originally sold for $369.00 is on sale at a 40% discount? How much will you pay for the coat?
Triss [41]
The coat will cost $221.40. If you move a decimal two spaces to the left from 40% (.40) and multiply it by $369.00, you'll get $147.60. You then subtract $147.60 from $369.00 and get $221.40, the final price of the coat.

5 0
2 years ago
Read 2 more answers
Please help me :)<br><br>....................​
natali 33 [55]

Answer:

hope this helps you!!!!!!!!!!

8 0
2 years ago
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