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3 years ago

NEED ASAP1.Factor the expression completely.

Mathematics

1 answer:

ella [17]3 years ago

5 0

Answer:

1. -5x(x+7)

2. the answer is A and D

3.(2x+1)(2x-3)

4. D

5. 3(x+4)(2x-3)

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Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro

lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that $\mu = 0, \sigma = 1$

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-1.69 - 0}{1}$

$Z = -1.69$

$Z = -1.69$ has a p-value of 0.0455

X = -2.23

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-2.23 - 0}{1}$

$Z = -2.23$

$Z = -2.23$ has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0

3 years ago

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

7 0

3 years ago

What is the area of the composite figure? ___ units^2

elena-14-01-66 [18.8K]

Answer:

34 square units

Step-by-step explanation:

The figure can be considered to be a trapezoid with a rectangle removed.

The area of the trapezoid is ...

A = (1/2)(b1 +b2)h

A = (1/2)(10 +6)(5) = 40

The area of the rectangle is ...

A = LW

A = (3)(2) = 6

Then the area of the shaded portion of the figure is ...

shaded area = trapezoid area - rectangle area

= 40 - 6 = 34 . . . square units

7 0

3 years ago

Given (64y^2)+(4x^2)+128y+16x+64=0, transform the equation into the appropriate form

____ [38]

Answer:

(8y+8)²+(4x²+16)=0

Step-by-step explanation:

Given:

(64y²)+(4x²)+128y+16x+64=0

Find:

Equation into the appropriate form

Computation:

(64y²)+(4x²)+128y+16x+64=0

(8y)²+(2x)²+128y+16x+64=0

(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0

(8y+8)²+(4x²+16)=0

6 0

3 years ago

Please help asap oiuytyghjkjhugytfhjkl

Alika [10]

Answer:

112

Step-by-step explanation:

correct me if im wrong.

I got this from doing 30 percent out of 160

160×0.30

160-48=112

7 0

3 years ago

Read 2 more answers