Answer:
1C is the correct answer.
Answer:
2.5e-0.04x = 1.2 + 0.2x
Step-by-step explanation:
Given that:
Insect A:
Initial population, Po = 2.5 million
Rate of decline = 4%
Insect B:
Initial Population (Po) = 1.2 million
Yearly increase = 200,000 = (200,000/1,000,000) = 0.2
For insect A:
P(t) = Po(1 - r)^t = Po*e^-rt
Po*e^-rt = 2.5e^-0.04t ----(1)
For Insect B:
P(t) = Po + (yearly increase) * t
P(t) = 1.2 + 0.2t - - - - - (2)
Equating (1) and (2)
2.5e^-0.04t = 1.2 + 0.2t
Answer:
2(3x+2) is your answer because you factor out 2. The number 2 is a factor of both 6 and 4 (2*3=6 and 2*2=4).
Seven because 1+2 is 3 and 3+1 is 4 so in total is seven