Answer: In the equations that you have given, we have a dependent system.
2x + y = 8 (I assumed that you meant to type y instead of 7)
6x + 3y = 24
To use Cramer's Rule, we have to take the determinant of 3 different matrices written in the problem. Taking the determinant of the coefficient matrix produces a zero.
2 1 This is the coefficient matrix.
6 3
6 - 6 = 0
Since this is 0, the rest of the work will be undefined meaning the systems are dependent (or they are the versions of the same equation).
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
expression
A mathematical symbol, or combination of symbols, representing a value, or relation. Example: 2+2=4
