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ipn [44]
2 years ago
14

In a booster club, 1/8 of the 128 members are men. How many male members are in the club?

Mathematics
2 answers:
Novay_Z [31]2 years ago
5 0
16 or B. Because  128 divided by 8 is 16
saul85 [17]2 years ago
5 0
B. 128/8=16 16*1=16 That's why the answer is b. 
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Jill went shopping from 3:45 pm to 5:00 pm for how long did she shop​
Eduardwww [97]

Answer:

total 1 hour 15 mins

Step-by-step explanation:

3:45 - 5:00

lets count one by one

3:45 - 4:00 = 15 mins

4:00 - 5:00 = 1 hour

total 1 hour 15 mins

3 0
2 years ago
If 2.5 is a root of the equation 2x^2+5x−q=0, what are the possible values of q?
bulgar [2K]

Answer:

q = -2510 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

Step-by-step explanation:

Grab the generic solution of the equation. \frac 52 = \frac{-5 \pm \sqrt{5^2-4*2*q}}{2*2}. Let's isolate the radical, and square both sides.10 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

4 0
3 years ago
Read 2 more answers
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

                                          = 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then,
Travka [436]

Answer:

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

<em>Check</em>

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.

6 0
3 years ago
If 83 : 45 :: 72 : ? solve and find the answer​
olga55 [171]

Answer: x=\dfrac{3240}{83}

Step-by-step explanation:

Given: 83 : 45 :: 72 : ?

Let unknown quantity (?) be x.

Now, x : y :: a : b

\Rightarrow\ \dfrac{x}{y}=\dfrac{a}{b}

83 : 45 :: 72 : x

\Rightarrow\ \dfrac{83}{45}=\dfrac{72}{x}\\\\\Rightarrow\ x=\dfrac{72}{83}\times45\\\\\Rightarrow\ x=\dfrac{3240}{83}

Hence, x=\dfrac{3240}{83}

7 0
2 years ago
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