What would you like help with?
Answer:
So we know the formula to calculate the area of the circular sector:
S=(r^2*π*a)/306°=
(5^2*3.14*40°)/360°= (1000*3.14) /360=8.72cm^2 so the right alternative should be the first one ,A.
Step-by-step explanation:
r - radius of the circle
a - corner of the circular sector
S - surface
AA = $1
AAA= $0.75
AA + AAA = 42
$1AA + $0.75AAA= $37
AA + AAA = 42
AA + AAA-AAA= 42- AAA
AA = 42- AAA
$1(42- AAA) + $0.75AAA= $37
$42 - AAA +0.75AAA = $37
$42 -0.25AAA= $37
$42-$42 -0.25AAA= $37 -$42
-0.25AAA= -5
-0.25AAA/-0.25 = -5/-0.25
AAA= 20
AA + AAA= 42
AA + 20 = 42
AA +20 -20 = 42-20
AA= 22
Check
$1AA + $0.75AAA= $37
$1(22)+ $0.75(20)= $37
$22 + $15 =$37
$37 = $37
The answer is the third option which is AEF and FED, AEG and CEG
Background: log (a . b) = log a + log b
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
= 4 + log x
therefore the graph of log(10000x) is just the graph of log x transposed by 4
