Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
Answer:
The given statement is "True".
Step-by-step explanation:
A statistical analytical technique that divides the perceived aggregate unpredictability present throughout an information source even further into 2 components.
- Systemic components
- Random components
If relevant information yet another category independent variable, as well as another quantifiable variable of interest, has been obtained, are using a single-way ANOVA.
Thus the above is the true answer.
X² + 2x +3
If the discriminent Δ = b²-4.a.c <0 , that means the roots (or the zero value) are nit REAL Number (they are imaginary or complex)
Δ = 2² - 4(1)3) = 4 - 12 = -8
since Δ = - 8 < 0 there are no real roots
Answer: y = 
<u>Step-by-step explanation:</u>
y = ax² ; where a represents the vertical stretch
a reflection across the x-axis is represented by making the a-value negative.
Its b because the equation pretty much says that is fx is gx when x is subtracted by 2
