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ZanzabumX [31]
3 years ago
6

Which of the following is a substance that is found between the cell membrane and the nucleus, which primarily consists of water

and holds organelles?
Physics
1 answer:
Alex3 years ago
5 0
This would be Cytoplasm , hope this helps 

Hugs

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What is the angular momentum of a 0.25 kg mass rotating on the end of a piece of
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L = r x p = rmv = mr²ω

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2 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

5 0
3 years ago
Strzała o masie 20g tuz po wystrzale ma prędkość 50m/s. Oblicz pracę wykonana przez zawodniczkę. Ile wynosi energia potencjalna
garri49 [273]

Answer:

Explanation:

masie m = 20g = 20/1000 = 0.02kg

prędkość v = 50m/s

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P.E = ½ × 0.02 × 50²

P.E = 25 J

pracę wykonana = P.E = 25J

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I would say the answer should be B it will go higher then 40m but not as high as 104.9
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1= temperature

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