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Nana76 [90]
3 years ago
10

Find the GCF of each set of numbers. 12, 21, 30 Math

Physics
2 answers:
svetlana [45]3 years ago
8 0

Answer:

3 is the GCF for all these numbers if thats what you're asking

natima [27]3 years ago
5 0
3 because
12=2’2x3
21=3x7
30=2x3x5
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6. What is the resultant force on each car below? Remember TWO pieces of
tamaranim1 [39]

Explanation:

In first case, the forces on LHS and on RHS is the same i.e. 3 N. The force acting on the car is balanced force. As a result, the car will not move at all.

In second case,

Force on RHS = 2000 N

Force on LHS = -6000 N

Net force acting on it is given by :

F = 2000+(-6000)

= -4000 N

Hence, this is the required solution.

4 0
2 years ago
A wheel rolling on a horizontal surface with an angular speed of 2.5 rad/s gets on a ramp and rolls down the ramp with a constan
STALIN [3.7K]

Answer:

the final angular speed of the wheel at the bottom is 25.5 rad/s

Explanation:

The computation of the final angular speed of the wheel at the bottom is as follows:

As we know that

W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s

Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s

We simply applied the above formula so that the final angular speed could come

7 0
3 years ago
A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. C
lozanna [386]

Hello!

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

We have the following data:

* velocity (in mph)

(V1) = 35.0 mph

(V2) = 40.0 mph

(V3) = 50.0 mph

* weights for the time (in hours)

(T1) = 1.00 hour

(T2) = 0.0500 hour

(T3) = 2.00 hours

We apply the data to the weighted average formula to find the average speed, let us see:

Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}

Weight\:Average = \dfrac{35.0*1.00+40.0*0.0500+50.0*2.00}{1.00+0.0500+2.00}

Weight\:Average = \dfrac{35+2+100}{3.05}

Weight\:Average = \dfrac{137}{3.05}

Weight\:Average = 44.91803279...

\boxed{\boxed{Weight\:Average = 44.92\:mph}}\Longleftarrow(Average\:Speed)\:\:\:\:\:\:\bf\purple{\checkmark}

Answer:

The Average Speed is approximately 44.92 mph

_______________________

\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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3 years ago
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Which point has the greatest electric potential energy?
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Answer:

D on Edge

Explanation:

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A boy pulls a wagon with a force of 6N east as another boy pushes it with a force of 8 N
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Answer:

14N

Explanation:

4 0
2 years ago
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