The distance measured from trough to trough or crest to crest of a wave is called the
2 answers:
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Answer:
T = 0.607 seconds
Explanation:
Given:
Mass, M = 1.50 × 10⁻² kg
Radius, R = 5.50 × 10⁻² m
Now,
the time period in terms of moment of inertia is given as:
.....................1
where, T is the time period
g is the acceleration due to gravity
I is the moment of inertia
Now,
Moment of inertia, I is given as:
on substituting the moment of inertia in the equation 1, we get
or
on substituting the valeus, we get
or
T = 0.607 seconds
Hence, the time period is 0.607 seconds
Answer:
a) v = 3,843 m / s, b) 46.7º North- East
Explanation:
Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.
The system is formed by the two vehicles so that the moment is preserved during the crash
Direction to the East
initial instant. Before the crash
p₀ = mₐ vₐ₀
final insttne. After the crash
p_f = (mₐ + m_b) vₓ
p₀ = p_f
mₐ vₐ₀ = (mₐ + m_b) vₓ
vₓ =
let's calculate
vₓ =
vₓ = 2,636 m / s
direction north
initial p₀ = m_b v_{bo}
final p_f = (mₐ + m_b) v_y
p₀ = p_f
m_b v_{bo} = (mₐ + m_b) v_y
v_y =
let's calculate
v_y =
v_y = 2.796 m / s
the final speed of the two two vehicles is
v = (2,636 i ^ + 2,796 j ^) m / s
a) the magnitude of the velocity
let's use the Pythagorean theorem
v =
v =
v = 3,843 m / s
b) let's use trigonometry to find the direction
tan θ = v_y / vₓ
θ = tan⁻¹ v_y / vₓ
θ = tan⁻¹ (2,796 / 2,636)
θ = 46.7º
This direction is 46.7º North East