1. rational 2. irrational 3. irrational 4. rational
Answer:
<u>First figure:</u> 
<u>Second figure:</u> 
<u>Third figure:</u>
- Height= q
- Side length = r
<u>Fourth figure: </u> 
Explanation:
<u></u>
<u>A. First figure:</u>
<u>1. Formula:</u>

<u>2. Data:</u>
<u>3. Substitute in the formula and compute:</u>

<u>B. Second figure</u>
<u>1. Formula: </u>

<u>2. Data:</u>
<u>3. Substitute and compute:</u>

<u></u>
<u>C) Third figure</u>
a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.
When the base of the pyramid is a square the four edges of the base have the same side length.
<u>D) Fourth figure</u>
<u>1. Formula</u>
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

<u>2. Data: </u>
- side length of the base: 11 cm
<u>3. Calculations</u>
a) <u>Calculate the area of the base</u>.
The base is a square of side length equal to 11 cm:

b) <u>Volume of the pyramid</u>:

Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
Answer:
1. 625,000 J
2. 100 J
4. 5 kg
5. √5 ≈ 2.236 m/s
Step-by-step explanation:
You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².
To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.
In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.
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1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J
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2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J
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4. KE = (1/2)<em>m</em>v²
250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²
(250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg
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5. KE = (1/2)<em>m</em>v²
2000 kg·m²/s² = (1/2)(800 kg)v²
(2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²
v = √5 m/s ≈ 2.236 m/s