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3 years ago

A theatre holds 1200 people when full.If it is 80% full,how many people are present

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

0.8 times 1200 is 960, which is the number of people when the theatre is 80% full.

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A watch gains 18 seconds in a day. how many minutes will the watch gain in 3 weeks?

nordsb [41]

6.3 minutes: 6 minutes and 20 seconds, I believe.

7 0

3 years ago

Read 2 more answers

Question 7 il pont) (2 +377)(2 – 377)

Elden [556K]

Answer:

142125

Step-by-step explanation:

Since we given two brackets to solve we will have to take the step by step procedure

So let's solve the question

(2+377)(2-377)

Let's start with the first bracket

(2+377)

It will give us 379

So let's solve the second bracket

(2-377)

It will give us -375

So back to the question

(379)(-375)

142125

So the final answer is 142125

3 0

3 years ago

Using the identity sin? O + cos? O = 1, find the value of tan O, to the nearest

Novosadov [1.4K]

Answer:

3.7

Step-by-step explanation:

Given

sin²θ + cos²θ = 1
sinθ = 0.27

Solving for cosθ

cos²θ = 1 - sin²θ
cos²θ = 1 - (0.27)²
cos²θ = 0.0729

Finding tanθ

tanθ = sinθ / cosθ
tanθ = 0.27 / 0.0729
tanθ = 3.7

Verifying it lies in the range

θ = tan⁻¹ (3.7)
θ = 74.88°
Range is : 0 < θ < π/2 [or 0 < θ < 90°]
It lies in the range [Verified]

7 0

2 years ago

Direct mail advertisers send solicitations ("junk mail") to thousands of potential customers in the hope that some will buy the

harina [27]

Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

1. Conditions

First we must check the conditions.

Randomization condition: The sample is given to be random, so we can assume independence.

Success/failure condition: Both np>10 and nq>10 must be met.

np = 1030(103/1030) = 103 ✓
nq = 1030(927/1030) = 927 ✓

10% condition: The sample cannot be greater than 10% of the population.

10n < N, 10(1030) < 200000 ✓

All conditions are met, so we can use a 1-proportion z-interval to represent the data.

2. Mechanics

Find $\hat{p}$ , the sample proportion.

103/1030 = .1

$\hat{q}$ , then, the probability of not p, is 1 - .1 = .9

Find z* (z star), the critical z-value.

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

Plug values into the equation.

$\hat{p}$ ± z* $\sqrt{\frac{\hat{p}\hat{q}}{n} }$

.1 ± 1.96 $\sqrt{\frac{.1*.9}{1030} }$

.1 ± 1.96(.00935)

.1 - .0183 = .0817

.1 + .0183 = .118

(.0817, .118)

3. Conclusion

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

5 0

3 years ago

Can someone help me with this question?

Masteriza [31]

Answer:

V=2c

Step-by-step explanation:

$\\[Looking at the relationship of the numbers in the table, we can see which ones will work right off the bat.]\\[Our first numbers are both zero, so we cant do anything significant there.]\\[Next row, however, we can start doing the process of elimination.]\\\left[\begin{array}{ccc}1&2\\2&4\\3&6\\4&8\\5&10\end{array}\right]\\ \\[After plugging in the formulas to see if they're true, the only one that works every time is V=2c.]\\[That is your answer.]$

6 0

3 years ago