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4 years ago

Question 2

1 answer:

3 0

The Y- intercept is (0,7) if The equation is Why equals -3 over 5X +7 (meaning a fraction)

if the equation is Y equals -3÷5 X +7 then the answer is: not linear

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The intersection of two colonel Lines is

Hunter-Best [27]

Answer:Two colonel lines

Step-by-step explanation:

It just is

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3 years ago

Help me understand this problem

Kryger [21]

It ΔABC and ΔXYZ are similar, then the sides of the triangles are in proportion.

$\dfrac{AB}{XY}=\dfrac{BC}{YZ}=\dfrac{AC}{XZ}$

We have BC = 8, AC = 7, Y = 28, XZ = 49 and YZ = 56. Substitute:

$\dfrac{AB}{XY}=\dfrac{BC}{YZ}\to\dfrac{AB}{28}=\dfrac{8}{56}\qquad\text{cross multiply}\\\\56AB=(8)(28)\qquad\text{divide both sides by 56}\\\\AB=\dfrac{224}{56}\\\\\boxed{AB=4}$

6 0

4 years ago

What two numbers add to -4 and multiply to -77

Vlad1618 [11]

-11x7=-77

-11+7=-4
Hope it helps

5 0

3 years ago

Read 2 more answers

A bag contains 7 milk and 5 dark chocolates. A sweet is selected at random. What is the probability of choosing: P(milk) = P(not

Sauron [17]

Answer: P(7)=P(5)=12

Step-by-step explanation:

4 0

3 years ago

7. These values represent the expected number of paintings a person will produce over the next 10 days. 0, 0, 0, 1, 1, 1, 2, 2,

Natasha_Volkova [10]

The mean of a dataset is the average of the dataset.

The mean is 1.5
The standard deviation is 1.58
The median remains unchanged, the mean increases, and the standard deviation decreases when 5 is increased to a larger value

The given parameters are:

$\mathbf{x = 0, 0, 0, 1, 1, 1, 2, 2, 3, 5}$

(a) Mean and Standard deviation

The mean of the dataset is calculated using:

$\mathbf{\bar x = \frac{\sum x}{n}}$

So, we have:

$\mathbf{\bar x = \frac{0+ 0+ 0+ 1+ 1+ 1+ 2+ 2+ 3+ 5}{10}}$

$\mathbf{\bar x = \frac{15}{10}}$

$\mathbf{\bar x = 1.5}$

Hence, the mean is 1.5

The standard deviation is calculated using:

$\mathbf{\sigma_x = \sqrt{\frac{\sum(x - \bar x)^2}{n - 1}}}}$

So, we have:

$\mathbf{\sigma_x = \sqrt{\frac{(0 - 1.5)^2 + (0- 1.5)^2 + (0- 1.5)^2 + (1- 1.5)^2 + (1- 1.5)^2 + (1- 1.5)^2 + (2- 1.5)^2 + (2- 1.5)^2 + (3- 1.5)^2 + (5- 1.5)^2}{10 - 1}}}$