Answer:
2(x+10) = 3x-30 (reason: vertical angles are congruent)
2x+20 = 3x-30
20 = 1x-30
1x = 20+30
1x = 50
x = 50
Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer:
39.75
Step-by-step explanation:
First, subtract 50 from both sides
200z + 50 - 50 = 8000 - 50
200z = 7950
Then isolate the variable by dividing both sides by 200
200z/200 = 7950/200
z=39.75
11,220,000,000 is the answer for this question.