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Naya [18.7K]
2 years ago
9

How many integers between 360 and 630 are there such that they have odd number of divisors?

Mathematics
1 answer:
Kryger [21]2 years ago
6 0

Answer:

7

Step-by-step explanation:

Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors "

Find all the squared values that lies between 360 and 630

360< 19², 20², 21², 22², 23², 24², 25² < 630

19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.

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Andrew [12]

Answer:

V = -9

Step-by-step explanation:

-15V - 40 = 23 - 8V

The objective is to get V alone. To do this, first subtract -15V from both sides. Since -15V is a negative, subtracting it will be adding a positive.

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Now that there is only one term with the variable V, subtract 23 from both sides.

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Finally, divide both sides by 7 to get V completely isolated.

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The final answer is V = -9.

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(Please mark be brainliest)

</span>
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