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2 years ago

How many integers between 360 and 630 are there such that they have odd number of divisors?

Mathematics

1 answer:

Kryger [21]2 years ago

6 0

Answer:

Step-by-step explanation:

Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors "

Find all the squared values that lies between 360 and 630

360< 19², 20², 21², 22², 23², 24², 25² < 630

19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.

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use the ruler provided to measure the base of the parallelogram shown to the nearest 0.5 CM which measurement is the closest to

valkas [14]

Answer:

Area of the parallelogram = 21.6 cm²

Step-by-step explanation:

Area of a parallelogram = Base × Height of the side parallel to the base

By using ruler,

Base = 4.8 cm

Height of parallelogram = 4.5 cm

Area of the parallelogram = 4.8 × 4.5

= 21.6 cm²

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2 years ago

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Answer:

Step-by-step explanation:

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gladu [14]

B = bees, w = wasps, x = hornets

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b = 3x - 9
w = x + 28

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5x = 184 - 19
5x = 165
x = 165/5
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2 years ago

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traingle ABC has been dilated aboit point A by a scale factor of 1/3. What are the lengths, in units, of the three sides of tria

solniwko [45]

Answer:

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Step-by-step explanation:

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2 years ago

SOS HURRY

Burka [1]

First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.

Distance formula:

$\sqrt{(x.2 - x.1)^{2} + (y.2 - y.1)^{2}}$

√((-2 + 5)^2 + (-8 + 4)^2)

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2 years ago