![\huge \pink\star\huge{ \pink{\bold {\underline {\underline {\red{Answer }}}}}}](https://tex.z-dn.net/?f=%5Chuge%20%5Cpink%5Cstar%5Chuge%7B%20%5Cpink%7B%5Cbold%20%7B%5Cunderline%20%7B%5Cunderline%20%7B%5Cred%7BAnswer%20%7D%7D%7D%7D%7D%7D%20%20)
➭Doing it all using mental math
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<u>Step 1:</u></h2>
![1037 + 4 \\ =1041](https://tex.z-dn.net/?f=%201037%20%2B%204%20%5C%5C%20%20%3D1041)
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<u>Step 2:</u></h2>
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Answer: (12,0)
Steps:
First, put the equation in slope-intercept form.
y=mx+b
1.5x + 4.5y =18
Subtract 1.5x from both sides.
4.5y =-1.5x +18
Divide both sides by 4.5 to isolate y.
y = -1/3x + 4
Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.
0 = -1/3x + 4
Subtract 4 from both sides
-4 = -1/3x
Divide both sides by -1/3 to isolate the x
12=x
Answer:
The answer is 115/1957 and in decimal form is 0.0558634
Step-by-step explanation:
Answer:
128 Boxes
Step-by-step explanation:
6 dozen = 72
9216 / 72 = 128
Answer:
The motorist's average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
Step-by-step explanation:
Let the motorist's average rate in the afternoon = <em>x</em> mph.
It is given that his average rate in the morning was twice his average rate in the afternoon.
Therefore, his average rate in the morning = 2<em>x</em> mph.
Let <em>t</em> be the time taken for the morning trip.
It is given that he spent 5 hours for driving.
So, the time taken by him for the afternoon trip = 5 - <em>t</em>.
Now, using the formumla,
,
the verbal model for the morning trip is:
![2x=\frac{150}{t}](https://tex.z-dn.net/?f=2x%3D%5Cfrac%7B150%7D%7Bt%7D)
<em>xt</em> = 75
The verbal model for the afternoon trip is:
![x=\frac{50}{5-t}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B50%7D%7B5-t%7D)
5<em>x</em> - <em>xt</em> = 50
Substituting <em>xt</em> = 75, we get,
5<em>x</em> - 75 = 50
5<em>x</em> = 125
<em>x</em> = 25
2<em>x</em> = 50
Hence, his average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.