Question

According to Ohm’s Law, the voltage V , current I , and resistance R in a circuit are related by the equation V = I R , where the units are volts, amperes, and ohms. Assume that the voltage is constant with V = 20 V. Calculate the average rate of change of I with respect to R for the interval from R = 6 to R = 6.1 . (Use decimal notation. Give your answer to three decimal places.)

Answer 1

Answer:

The average rate of change as follows of I is -0.185.

Step-by-step explanation:

The relation between voltage V, current I, and resistance R in a circuit, according to the Ohm's law is:

$V = IR$

It is provided that:

V = 20 V

The interval between which R varies is, R = 8 to R = 8.1.

Compute the value of I as follows:

$V=IR\Rightarrow I=\frac{I}{R}\Rightarrow I=\frac{20}{R}$

Compute the average rate of change as follows of I as follows:

$\frac{\delta I}{\delta R}=\frac{(I\times8.1)-(I\times8)}{8.1-8}$

    $=\frac{1}{0.1}[\frac{12}{8.1}-\frac{12}{8}]$

    $=\frac{12}{0.1}[\frac{8-8.1}{64.8}]$

    $=-0.1852$

Thus, the average rate of change as follows of I is -0.185.