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Lemur [1.5K]
3 years ago
9

Describe the effect f(1/4x) will have on the function f(x)

Mathematics
1 answer:
GaryK [48]3 years ago
8 0
It will quarter the result. (I think so)
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Alex wrote checks on Tuesday for $30 and $40. He also made a deposit in his
Ksivusya [100]

Alex finally had $(x+110) amount of money in his account i.e. He had $100 more then before!

<u>Step-by-step explanation:</u>

Alex wrote checks on Tuesday for $30 and $40. He also made a deposit in his checking account of $180. Let's solve it step by step :

<u>Alex wrote checks on Tuesday for $30 and $40:</u>

Let's suppose Alex initially had x amount of money out of which $30 & $40 is deducted! so left amount of money is $(x-70) .

<u>He also made a deposit in his checking account of $180:</u>

Out of left money $(x-70) , Alex deposited $180 in account so new money = $(x-70) + $180 = $(x+110)

Therefore, Alex finally had $(x+110) amount of money in his account i.e. He had $100 more then before!

6 0
3 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
A company makes triangular plates for individual slices of pizza. For each plate, the base is 7 inches and the height is 12 inch
kaheart [24]
42 inches squared

base times height divided by two

7x12 divided by two is 42

8 0
3 years ago
Read 2 more answers
Problems<br>Simplity each expression 4(9+8)​
Pepsi [2]

36+32 << multiply

68 << add

4 0
3 years ago
Read 2 more answers
Alpha company has assets of $602,000, liabilities of $251,000, and equity of $351,000. it buys office equipment on credit for $7
ipn [44]
As we know assets = liabilities + equity

In this case assets would be increased by $76,000 and the liabilities would be increased by $76,000

Did I answer your question, or did you mean something else?
3 0
3 years ago
Read 2 more answers
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