Answer:
Given two events A and B of a sample set :-
P[A] = 0.20
P[not B]=0.40
![P[B/A]=0.25](https://tex.z-dn.net/?f=P%5BB%2FA%5D%3D0.25)
To find P[A or B]:
......[1]
Calculate for
and ![P[A \cap B]](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D)
P[B] = 1- P[not B]
Substitute the value P[not B] we get;
P[B] = 1-0.40 = 0.60
![P[A \cap B] = P[B/A] \cdot P[A]](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D%20%3D%20P%5BB%2FA%5D%20%5Ccdot%20P%5BA%5D)
Substitute the given values we get;
![P[A \cap B] = 0.25 \cdot 0.20 = 0.05](https://tex.z-dn.net/?f=P%5BA%20%5Ccap%20B%5D%20%3D%200.25%20%5Ccdot%200.20%20%3D%200.05)
Then;
Therefore, the value of P[A or B] is, 0.75.
Dec 20, 2014 - <span>The </span>volume V<span> of a right circular </span>cylinder<span> of </span>height h<span> and </span>radius r<span> is </span>V=pr^2h<span>. If the </span>height<span>is twice the </span>radius<span>, express the </span>volume V<span> as a function of r ... Hi Tammie,. OK so we have the </span>volume<span>formula. </span>V=(pi)<span>r2h</span><span>. and we know that </span>h<span> = 2r. so we can replace </span>h<span> with 2r and we get. </span>V<span> = (</span>pi)<span>r2</span>(2r).V=2(pi)r3<span>.</span>
Answer:pointssssssssssssssssssssssssssssss
Step-by-step explanation:
Answer:
ow that so hard
Step-by-step explanation:
wait let me see the answer i well search it
Answer:
16
Step-by-step explanation:
Hope this helps sorry if I'm wrong