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Veseljchak [2.6K]
2 years ago
14

Given z1 = 1 + i, z2 = 1 + i, find w = z1 ⋅ z2, and graph z1, z2, and w.

Mathematics
1 answer:
Dafna1 [17]2 years ago
5 0

We draw complex numbers as points, where the x,y coordinates are the real and imaginary part:

z = a+bi \mapsto (a,b)

So, we have

z_1 = z_2 = 1+i \mapsto (1,1)

So, both z_1 and z_2 are represented by the point (1,1).

Their product is

w=z_1\cdot z_2 = (1+i)^2 = 1+2i+i^2 = 1+2i-1=2i

And its representation is

w=2i = 0+2i \mapsto (0,2)

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Ymorist [56]

Part C:

y = total cost

M = minutes


You can talk on the phone only 100 minutes per month

Company A:

y = 0.04M + 5

y = 0.04(100) + 5

y = 4 + 5

y = 9             $9 per month


Company B:

y = 0.10M + 2

y = 0.10(100) + 2

y = 10 + 2

y = 12          $12 per month


Company A offers the best deal because at Company A you have to pay $9 for 100 minutes per month, and at Company B you have to pay $12 for 100 minutes per month, so you have to pay $3 less.


Part D:

1.) With a budget of $30, Company A would allow me to talk longer on the phone. I know this because for Company A, you pay $3 less per month for the same amount of minutes as Company B. This means that I will save more money with Company A, and I can buy more minutes. (something like this)


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3 years ago
A rule for creating a pattern is given in equation form below.
svetoff [14.1K]

ANSWER B

16=22-6

Do the math on paper and you should get it.

6 0
3 years ago
Read 2 more answers
A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

The 95 percent confidence interval estimate for the​ mean:(190.14, 295.06)

8 0
3 years ago
Really need this answered :/ thank you
VladimirAG [237]

Answer:

i believe its the third one don't quote me on that though

Step-by-step explanation:


5 0
3 years ago
Anthony borrowed $18,800 at 6% simple interest for 4 months. Determine the amount of interest.
anygoal [31]
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
putting time into years for simplicity,
4 months ÷ 12 months/year = 0.333333 years,
then, solving our equation

I = $ 376.00

I = 18800 × 0.06 × 0.333333 = 375.999624
I = $ 376.00

The simple interest accumulated
on a principal of $ 18,800.00
at a rate of 6% per year
for 0.333333 years (4 months) is $ 376.00.
5 0
2 years ago
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