Ask question

Ask question

All categories

2 years ago

5

A mountain peak is 12,200 feet above sea level. The valley below is 218 feet below sea level. How far is it from the peak to the

valley?

2 answers:

professor190 [17]2 years ago

8 0

Answer:

11782 is the answer I got

Step-by-step explanation:

Lady bird [3.3K]2 years ago

7 0

11782 i may be wrong but i think i’m right

You might be interested in

4 times a number is greater than -48.what are the possible values for the number ?

Keith_Richards [23]

The answer might be - 12

4 x -12 = 48

7 0

2 years ago

PLEASEEE HELP!!!!! (brainliest)

lesya692 [45]

The answer should be 2d-20.

Need an explanation?

8 0

2 years ago

Please help me w/ this geometry question. <br><br> image attached.

-BARSIC- [3]

Not enough information to answer; Only 2 angles are given, no other information is provided. So no information can be drawn from the problem, therefore the answer is A, not enough information.

3 0

2 years ago

A water bottle holds 3 1/3 c of water. A bowl holds 2 1/4 times the amount in the water bottle. How much water does the bowl hol

kodGreya [7K]

First you would put both numbers into improper fractions.

3 1/3 = 10/3 and 2 1/4 = 9/4

Multiply 10/3 * 9/4

10*9 = 90 and 3 * 4 =12

So 90/12 is your fraction. Reduce it, 7 6/12

7 6/12 = 7 1/2

So your answer is 7 1/2

Hope I helped :)

7 0

2 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

2 years ago