Answer:
6.04 g O2
Explanation:
6.80 g H2O x (1 mol/18.0 g) x (1 O2/2 H2O) x (32.0 g/1 mol) = 6.04 mol O2
Answer:
One mole of CO2 has mass of 44 g and 32 g of O2. So 16 g of O2 have 22 g of CO2 or 0.5 moles of it.
brainliest plz
Explanation:
Answer:
sir/ma'am, i know i'm a <u>NOOB</u> at this kind of stuff but i believe it's oxygen.
Explanation:
i can't really remember the answer since it's been a week or so that i done this problem, it's between nitrogen and oxygen, though, i believe it's oxygen.
if ya don't believe me or trust me, then here's the link to help ya:
https://socratic.org/questions/what-elements-would-have-similar-properties-to-sulfur#628367
Answer:
The woodpecker population would start to decrease because of natural selection
Explanation:
There are 1.22 grams of He in the mixture. The mixture contains 0.304 moles of He, 0.250 moles of N2 and 0.250 moles of O2. Since the mixture of gases are at standard temperature and pressure, the total moles of the mixture equivalent to 18.0 L is 0.804 moles.
Further Explanation:
At standard temperature and pressure of 0°C and 1.00 atm, the molar volume of gas is 22.4 L.
From this, the total moles of the mixture can be derived using the solution below:
Therefore, the total moles of gases in an 18.0 L mixture at STP is:
By algebra, the moles of He may be solved using the given moles of the other two gases: 0.250 mol N2 and 0.250 mol O2.
0.304 moles of He is equal to 1.22 grams of He.
Learn More:
- Learn more about Boyle's Law brainly.com/question/12968820
- Learn more about Gay-Lussac's Law brainly.com/question/6534668
- Learn more about Ideal Gas Law brainly.com/question/12935899
Keywords: molar volume, STP, stoichiometry