Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol
Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol
Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ
Answer:
26,7 g
Explanation:
![8,9[\frac{g}{cm^3}]*3[cm^3]=26,7[g]](https://tex.z-dn.net/?f=8%2C9%5B%5Cfrac%7Bg%7D%7Bcm%5E3%7D%5D%2A3%5Bcm%5E3%5D%3D26%2C7%5Bg%5D)
As you see in the maths, if you have 8,9 grams per each cubic centimeter, in 3 cubic centimeter you'll have 3 times 8,9
Answer:
Use PV = nRT. Don't forget T must be in kelvin.
Explanation:
Answer:
It does not matter what the solute is, but Yes, the same solute will dissolve differently in different solvents.
So sorry if it’s wrong but I hope this helps