1. s block elements have spherical s orbital as
their outermost orbital.
2. Since s orbital can accommodate a maximum of 2 electrons, each one of these elements have 1 or two electrons.
3. These s electrons are lost very easily to form
monopositive ions by Isoing one electron in the
outermost orbital or dipositive ions by losing 2
electrons.
4. They have low ionisation potentials and low electronegativities.
5. They are good conductors of heat and electricity, excepting H2 and He.
6. They are silvery, shiny metallic substances, (with the exception of hydrogen and helium which gaseous nonmetals).
7. They are malleable and ductile, i.e., we can
make sheets and wires from them, (exception:
H2, He)
8. They readily form ionic salts with most nonmetals.
hope it helps plzzz mark as brainliest
B. 0.9 <span>
</span>D.Light intensity has no effect on whether electrons are emitted or not.
and
A. X=1.9eV,Y=0.2eV
I already took the gizmo so I know these are right. The first one I got wrong b/c there was no graph and the last one I didn't understand. Basically for the last one you calculate the work function for the metals and find their difference.
Hope this helps.
Answer:a) 11.34 g of ethane can be formed
b) is the limiting reagent
c) 3.44 g of the excess reagent remains after the reaction is complete
Explanation:
To calculate the moles :
1.
2.
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.378 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
moles of left = (2.10-0.378) = 1.72 moles
mass of left=
According to stoichiometry :
As 1 mole of give = 1 mole of
Thus 0.378 moles of give = of
Mass of
Thus 11.34 g of ethane is formed.
Answer:
89,4%
Explanation:
If you have a solutio of 2,5g of acetanilide in 50mL of water and you warm this solution to 100°C you will dissolve all acetanilide because the maximum solubility in 50mL will be:
5,5g / 100mL → 2,75g / 50mL.
Then, if you cold the water to 0°C the solubility in 50mL will be:
0,53g / 100mL → 0,265g / 50mL.
That means you will precipitate:
2,5g - 0,265g = <em>2,235g of acetanilide</em>
The theoretical percent recovery will be:
2,2365g / 2,5g ×100 = <em>89,4%</em>
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I hope it helps!
The projectile is the bullet it's self. the chemicals create the explosion to project the bullet