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3 years ago

Which kingdom does spiny lobster, and diatom belong to?

Chemistry

1 answer:

Lemur [1.5K]3 years ago

3 0

Answer: The spiny lobster belongs to the kingdom ANIMALIA while diatoms belongs to the kingdom PROTISTA.

Explanation:

There are different ways biologists have used to examine and describe million kinds of living organisms. To classify organisms into groups, biologist look for important features that are shared by a large variety of organisms. These features which should have similar origin, structure and position. Organisms with certain important features in common are then put together into one group.

In the hierarchy of living organisms, the largest group of organisms is the KINGDOM. There are five types of kingdoms in which organisms are grouped, these includes:

--> kingdom Monera

--> kingdom PROTISTA,

--> kingdom fungi,

--> kingdom plantae and,

--> kingdom ANIMALIA.

Kingdom PROTISTA: they are single-celled, motile or non-motile organisms that are made up of eucaryotic cells, that is,cell structure is complex with a definite nucleus. Member include the DIATOMS, amoeba and chlamydomonas.

Kingdom ANIMALIA: They are multiple-celled, motile organisms that feed on other organisms. Their cells have no cell walls. The members include the SPINY LOBSTER, corals,worms, snails and cows

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Answer:

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Explanation:

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3 years ago

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AlekseyPX

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3 years ago

A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in K

SCORPION-xisa [38]

The temperature of the gas sample is 813 K.

Explanation:

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $$\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}$

= 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$$T= \frac{PV}{nR}$

T = $$\frac{0.56 \times 0.56}{0.08205 \times 0.0047}$

= 813 K

So the temperature of the gas sample is 813 K.

5 0

4 years ago