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lara31 [8.8K]
2 years ago
12

Hope this is better lol

Mathematics
2 answers:
vladimir2022 [97]2 years ago
8 0

Answer:

thanks

Step-by-step explanation:

taurus [48]2 years ago
4 0

Answer:

1) 5.75

2) -6.25

3) 3.75

4) -3.5

5) decreased by 3.3 gallons

Step-by-step explanation:

1) 8 - 2.25 = 5.25

2) - 3\frac{1}{2}  + (  - 2\frac{3}{4} )

=  >  \frac{ - 7}{2}   +  \frac{ - 11}{4}

=  >  \frac{ - 25}{4}  =6.25

3) 1 \frac{1}{4}  + 2 \frac{1}{2}

=  >  \frac{5}{4}  +  \frac{5}{2}

=  >  \frac{15}{4}  = 3.75

4) - 9.5 + 6 =  - 3.5

5)

Amount of water collected on a month = 8.4 gallons

Amount of water used in garden = 5.2 gallons

Amount of water used in flowers = 6.5 gallons

Total amount of water used up = 5.2 + 6.5 = 11.7 gallons

Dat gurl saved 8.4 gallons in that month & she used up 11.7 gallons water. So, the rainwater supply was decreased by (11.7 - 8.4) = 3.3 gallons

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48 inches

Step-by-step explanation:

There are 12 inches in 1 foot. So multiply by 12 to convert from feet to inches.

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4 feet = 48 inches

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Step-by-step explanation:

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3 years ago
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The radius of a circle 6 cm what is the circles area?
dolphi86 [110]

Answer:

113.04 cm

Step-by-step explanation:

We know the formula to find the area of a circle is

A= pi(r^{2})

And we are told to use 3.14 instead of pi so what we have now is,

A=3.14(r^{2})

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Now we have,

A=3.14(36)  

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Hope that helps and have a great day!

7 0
3 years ago
Evaluate the expression 8x for x=2
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2 years ago
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An instructor who taught two sections of engineering probability last term, the first with 20 students and thesecond with 30, de
Oliga [24]

Answer:

0.207

Step-by-step explanation:

This is an hypergeometric distribution problem

An hypergeometric distribution has the same sense as the discrete probabilities of binomial distribution, but unlike binomial distribution, hypergeometric distribution does not allow replacement.

Binomial distribution expresses the probability of picking k objects from n with replacement, but hypergeometric distribution expresses picking k objects from n without replacement, with the finite total population, N, containing K objects.

It is expressed mathematically as

h(k: n, K, N) = (ᴷCₖ)(ᴺ⁻ᴷCₙ₋ₖ)/(ᴺCₙ)

where

k = number of students in the 2nd section required to be in the first 15 graded projects (number of successes) = 10

n = total number of first graded projects (number of trials) = 15

K = number of students in the 2nd section of the class = 30

N = total number of students = 50

h(10: 15, 30, 50) = (³⁰C₁₀)(⁵⁰⁻³⁰C₁₅₋₁₀)/(⁵⁰C₁₅)

h(10: 15, 30, 50) = (³⁰C₁₀)(²⁰C₅)/(⁵⁰C₁₅)

= (30,045,015)(15,504)/(2,250,829,575,120)

P(X = 10) = 0.207

Hope this Helps!!!

7 0
3 years ago
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