f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
I'm pretty sure the answer is T/LS=x or in other words T divided by LS equals x.
We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
Answer:
10
Step-by-step explanation:
Means back the numbers into multiples of several small numbers
Like:; 1. We take LCM of 40
Just break into multiples of small number
40= 2×2×2×5
2. We take LCM of 50
50= 5×5×2
So LCM for 100 is 2×2×5×5
after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)
Then write the the single number in place of two multipled numbers
Like:; 2×2 is written as 2 // 3×3 is written as 3
So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)
write pairs in single number 2×5
And so we get 2×5=10
So we find root of 100 that is 10
Answer: The function that is represented by the equation y = negative 10 x + 6 has a steeper slope and a greater y-intercept.
Step-by-step explanation: I took the unit test on edge hoped this helped <3
