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Llana [10]
3 years ago
8

12-3m=4+5/m HELPPPP

Mathematics
2 answers:
Kipish [7]3 years ago
6 0
M1= 5 , M2=1

Explanation:

12-3m-4-5/m=0
8-3m-5/m=0
(8-3m-5/m=0) * m
8m-3m^2-5=0
8m-3m^2=5
m(8-3m)=5
m1=5
m2=> (8-3m)=5
3m=3
m2= 1
VladimirAG [237]3 years ago
4 0

Answer:

m=1\\m=\frac{5}{3}

Step-by-step explanation:

12 - 3m = 4 + \frac{5}{m}

8=\frac{5}{m} +3m

Multiply the whole thing by m

8m = 5 +3m^{2}

3m^{2} -8m + 5 = 0

(3m^{2} -3m) + (-5m +5)

3m(m-1)-5(m-1)=0

3m-5=1\\m-1=0

m=1\\m=\frac{5}{3}

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olga2289 [7]

Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

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On a school trip to a theme park, 4 busses each carry 70 students.
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Answer:

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Step-by-step explanation:

According To the Question,

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  • And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.

Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students

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Step-by-step explanation:

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9 ÷ 12 = 0.75

.75 × 12 = 9

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Answer:

y = 2

Step-by-step explanation:

y varies inversely with x setup is:

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