The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.
<h3>What is an area bounded by the curve?</h3>
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0
The intersection points will be
y₁ = y₂
4 - 4x² = 0
x = ±1
Then the area bounded by the curves will be
![\rm Area = \int _{-1}^1 (y_1- y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \](https://tex.z-dn.net/?f=%5Crm%20Area%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%28y_1-%20%20y_2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%284%20-%204x%5E2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cleft%20%5B%204x%20%20-%20%5Cdfrac%7B4x%5E3%7D%7B3%7D%20%5Cright%20%5D_%7B-1%7D%5E1%5C%5C%5C%5CArea%20%3D%204%20%5Cleft%20%28%201%20%2B%201%20%5Cright%20%29%20-%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cleft%20%28%201%5E3%20-%20%28-1%29%5E3%20%5Cright%20%29%5C%5C%5C%5CArea%20%3D%208%20-%20%5Cdfrac%7B8%7D%7B3%7D%5C%5C%5C%5CArea%20%3D%20%5Cdfrac%7B16%7D%7B3%7D%20%3D%205.333%20%5C)
More about the area bounded by the curve link is given below.
brainly.com/question/24563834
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Answer:
The answer is <u>-37</u>.
Step-by-step explanation:
1) Simplify 50-2 to 48.
48 ÷ 4 - 
2) Simplify
to 49.
48 ÷ 4 - 49
3) Simplify 48 ÷ 4 to 12.

4) Simplify.

<u>Therefor, the answer is </u><u>Option C) -37</u><u>.</u>
Answer:
10 2/4
Step-by-step explanation:
Answer:
21, 8
Step-by-step explanation:
The second endpoint is of the form (X, 8) since it's parallel to the x axis.
Given the congruence of the two segments, we can tell that its length is 16 units (since
)
At this point the two possible endpoints for the segment are
or
. The fact that the segment has to sit in the first quadrant rules out the first option (it's endpoint will be at (-11, 8) which will set most of it in the second quadrant) and we're left with (21, 8)