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bagirrra123 [75]
3 years ago
15

Use the table. Estimate the total deer population for year 8.

Mathematics
1 answer:
KiRa [710]3 years ago
3 0

Your answer is About 1815 deer

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The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

        x = ±1

Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

6 0
2 years ago
Find the value of this expression <br> (50 - 2) ÷ 4 - 7²<br><br> -40<br> -41<br> -37
UkoKoshka [18]

Answer:

The answer is <u>-37</u>.

Step-by-step explanation:

1) Simplify 50-2 to 48.

48 ÷ 4 - 7^{2}

2) Simplify 7^{2} to 49.

48 ÷ 4 - 49

3) Simplify 48 ÷ 4 to 12.

12 - 49

4) Simplify.

-37

<u>Therefor, the answer is </u><u>Option C) -37</u><u>.</u>

6 0
3 years ago
Can someone plz help me with this one problem plz I’m trying to get to a 70
MissTica

Answer:

10 2/4

Step-by-step explanation:

6 0
3 years ago
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Which graph represents inequality y &lt;2x+3
natta225 [31]
The answer is G, luv
7 0
3 years ago
the segments ab and cd are graphed on a coordinate plane. The endpoints of ab are at (9,4) and (9,20). CD is parallel to the x-a
Step2247 [10]

Answer:

21, 8

Step-by-step explanation:

The second endpoint is of the form (X, 8) since it's parallel to the x axis.

Given the congruence of the two segments, we can tell that its length is 16 units (since |4-20| = |-16|= 16)

At this point the two possible endpoints for the segment are (5-16; 8) or (5+16, 8). The fact that the segment has to sit in the first quadrant rules out the first option (it's endpoint will be at (-11, 8) which will set most of it in the second quadrant) and we're left with (21, 8)

5 0
3 years ago
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