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2 years ago

12

5 (2x-4)-3 (x-2)=4x-2

1 answer:

lutik1710 [3]2 years ago

5 0

Step-by-step explanation:

10x - 20 - 3x + 6 = 4x - 2

10x - 3x - 4x = 20 - 6 - 2

3x = 12

3x/3 = 12/3

x = 4

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3 years ago

Segment JL has endpoints J(-3, -4) and L(7, 6). What are the coordinate of point K, so that point K is on line segment JL and JK

VMariaS [17]

Answer:

K(3,2).

Step-by-step explanation:

We want to find a point K(x,y).

JK = 3/5 JL.

This means that:

$K - J = \frac{3(L - J)}{5}$

We use this to find both the x-coordinate and the y-coordinate of K.

x-coordinate:

x-coordinate of J: -3

x-coordinate of L: 7

$K - J = \frac{3(L - J)}{5}$

$x - (-3) = \frac{3(7 - (-3))}{5}$

$x + 3 = 6$

$x = 3$

y-coordinate:

y-coordinate of J: -4

y-coordinate of L: 6

$K - J = \frac{3(L - J)}{5}$

$y - (-4) = \frac{3(6 - (-4))}{5}$

$y + 4 = 6$

$y = 2$

The point is K(3,2).

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3 years ago

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Answer:

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2 years ago

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3 years ago

A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final leng

Andrej [43]

Answer:

The Poisson's ratio for the material is 0.0134.

Step-by-step explanation:

The Poisson's ratio ( $\nu$ ), no unit, is the ratio of transversal strain ( $\epsilon_{t}$ ), in inches, to axial strain ( $\epsilon_{a}$ ), in inches:

$\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}$ (1)

$\epsilon_{a} = l_{a,f}-l_{a,o}$ (2)

$\epsilon_{t} = l_{t,f}-l_{t,o}$ (3)

Where:

$l_{a,o}$ - Initial axial length, in inches.

$l_{a,f}$ - Final axial length, in inches.

$l_{t,o}$ - Initial transversal length, in inches.

$l_{t,f}$ - Final transversal length, in inches.

If we know that $l_{a,o} = 61.2\,in$ , $l_{a,f} = 61.235\,in$ , $l_{t,o} = 2.7\,in$ and $l_{t,f} = 2.69953\,in$ , then the Poisson's ratio is:

$\epsilon_{a} = 61.235\,in - 61.2\,in$

$\epsilon_{a} = 0.035\,in$

$\epsilon_{t} = 2.69953\,in - 2.7\,in$

$\epsilon_{t} = -4.7\times 10^{-4}\,in$

$\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}$

$\nu = 0.0134$

The Poisson's ratio for the material is 0.0134.

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3 years ago