1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Morgarella [4.7K]
4 years ago
6

Line r is parallel to line t. Find m angle 5 45 35 135 145

Mathematics
2 answers:
Dimas [21]4 years ago
6 0

Answer: 135 °

Step-by-step explanation:

We know that when twp parallel lines are intersected by a transversal then the alternate exterior angles are equal.   (1)

IN the given figure , we have two lines r and t parallel to each other.

Here, The one pair of exterior angles is m ∠ 5  and angle 135°.

From (1), m ∠ 5 = 135 °.  [∵ Alternate exterior angles made by parallel lines are equal.]

Hence, the measure of m ∠ 5 = 135 °.

Lelu [443]4 years ago
5 0
M angle 5 is 135 because they are the outer opposites
You might be interested in
How to determine if a graph is symmetrical
Lisa [10]

Answer:

If you fold it in half.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Brainly if it is correct
Musya8 [376]

Answer:

The third one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the 99 times x=4
Musya8 [376]
The answer i x=4/99  (fraction form )

4 0
3 years ago
Read 2 more answers
I need help with no.7
ziro4ka [17]

Answer:

  (a) 315°

  (b) 3°

  (c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

  315° +48° = 363°, or 3° . . . . bearing of Q from R

__

<h3>(c)</h3>

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

  180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

  135° -77° = 58°

As above, the reverse bearing from Q to P is ...

  58° +180° = 238° . . . . bearing of P from Q

8 0
3 years ago
For 0 ≤ ϴ &lt; 2π, how many solutions are there to tan(StartFraction theta Over 2 EndFraction) = sin(ϴ)? Note: Do not include va
Black_prince [1.1K]

Answer:

3 solutions:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

Step-by-step explanation:

So, first of all, we need to figure the angles that cannot be included in our answers out. The only function in the equation that isn't defined for some angles is tan(\frac{\theta}{2}) so let's focus on that part of the equation first.

We know that:

tan(\frac{\theta}{2})=\frac{sin(\frac{\theta}{2})}{cos(\frac{\theta}{2})}

therefore:

cos(\frac{\theta}{2})\neq0

so we need to find the angles that will make the cos function equal to zero. So we get:

cos(\frac{\theta}{2})=0

\frac{\theta}{2}=cos^{-1}(0)

\frac{\theta}{2}=\frac{\pi}{2}+\pi n

or

\theta=\pi+2\pi n

we can now start plugging values in for n:

\theta=\pi+2\pi (0)=\pi

if we plugged any value greater than 0, we would end up with an angle that is greater than 2\pi so,  that's the only angle we cannot include in our answer set, so:

\theta\neq \pi

having said this, we can now start solving the equation:

tan(\frac{\theta}{2})=sin(\theta)

we can start solving this equation by using the half angle formula, such a formula tells us the following:

tan(\frac{\theta}{2})=\frac{1-cos(\theta)}{sin(\theta)}

so we can substitute it into our equation:

\frac{1-cos(\theta)}{sin(\theta)}=sin(\theta)

we can now multiply both sides of the equation by sin(\theta)

so we get:

1-cos(\theta)=sin^{2}(\theta)

we can use the pythagorean identity to rewrite sin^{2}(\theta) in terms of cos:

sin^{2}(\theta)=1-cos^{2}(\theta)

so we get:

1-cos(\theta)=1-cos^{2}(\theta)

we can subtract a 1 from both sides of the equation so we end up with:

-cos(\theta)=-cos^{2}(\theta)

and we can now add cos^{2}(\theta)

to both sides of the equation so we get:

cos^{2}(\theta)-cos(\theta)=0

and we can solve this equation by factoring. We can factor cos(\theta) to get:

cos(\theta)(cos(\theta)-1)=0

and we can use the zero product property to solve this, so we get two equations:

Equation 1:

cos(\theta)=0

\theta=cos^{-1}(0)

\theta={\frac{\pi}{2}, \frac{3\pi}{2}}

Equation 2:

cos(\theta)-1=0

we add a 1 to both sides of the equation so we get:

cos(\theta)=1

\theta=cos^{-1}(1)

\theta=0

so we end up with three answers to this equation:

\theta={0, \frac{\pi}{2}, \frac{3\pi}{2}}

7 0
3 years ago
Other questions:
  • A bag contains 2 white marbles abd six black marbles.
    8·1 answer
  • If a famer plows 2 acres every 3 hours how long will it take to plow 60 acres
    7·1 answer
  • An aircraft carrier travels a distance of 1,000 km in 3 days. What is its average rate of speed?
    12·1 answer
  • List the first three terms of this sequence: an = 3 • 5n – 1
    12·1 answer
  • I will mark you brainlist!
    12·1 answer
  • Can somebody please help me out please my grads are bad
    14·1 answer
  • The length of a room is 23 1/2 feet. When using a 1/8 inch = 1 foot scale, find the length of
    15·1 answer
  • Help!! I spent hours trying to figure this out!! Answer was incorrect. And it has to be written in equation or fraction format.
    14·1 answer
  • This is due like right now, please help me!!!!
    7·1 answer
  • Is this function linear or exponential?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!