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seropon [69]
3 years ago
7

Please help me im almost done!​

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

if you divide both sides of -5x > 0 you get z > <em>0. </em>This is incorrect because if you choose a value from the possible solutions such as z=6 and substitute it into the original equation you get <em>-30</em> > 0, which is <em>not true</em>

I put the answers in bold

hope this helps!

Step-by-step explanation:

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Choose the equation that represents the line that passes through the point (2, 6) and has a slope of −5.
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Answer:

y=-5x+16

Step-by-step explanation:

Plug in the slope and point coordinates into point-slope form (attached in image)

(y-6)=-5(x-2)

1) Distribute -5 to x and -2:

y-6=-5x+10

2) Add 6 to both sides:

y=-5x+16

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Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
3 years ago
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