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k0ka [10]
3 years ago
11

g find all the values of p for which the following functions are improperly integrable on the indicated domain. be sure to prove

your claims, ie show that it is improperly integrable for those numbers p, but is not for other numbers 1.f(x)=1/x^p on i =(0,1) 2. f(x) = 1/(x(lnx)^p) on I = (e,inf)
Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

1. In order to make the integral improper  p  must be 1.

2. In order to make the integral improper  p  must be 1.  

Step-by-step explanation:

Using the rules of integration we get that for

f(x)= \frac{1}{x^p}

\int\limits_{0}^{1}  \frac{1}{x^p}  \, dx  = \frac{x^{1-p}}{(1-p)}  \, |\limits_{0}^{1}   = \frac{1}{1-p} - 0 = \frac{1}{1-p}

Therefore in order to make that integral improper  p  must be 1.

If  p = 1     then you would have a 1/0  indeterminate form.

2.   Using the of integration, specifically substitution we get that for

f(x) = \frac{1}{x(ln(x)^p)}

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{(ln(x))^{1-p}}{1-p} \, |\limits_{e}^{\infty}

For   p \geq 1  we would have

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{1}{p-1}

And the problem is the same.  If  p=1   we would have a 1/0 indeterminate form.

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8 Leandra's fastest time for the 400 m is 70 seconds. In his next race he improves by
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8) a) The new fastest time is 56.7 seconds, b) The <em>overall percentage</em> improvement is 19 %.

9) The height after the first increase is 1.375 meters and after the second increase is 1.54 meters.

<h3>How to apply percentages in real life applications</h3>

In this problem we have two examples from real life, in which percentages are used. The first is the distance traveled by a runner in a given time and the second is the growth of a person in time. Change in variables based on percentages are described by the following formula:

C' = C · (1 + r / 100)     (1)

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  • C' - Final value
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Now we proceed to resolve on each case. 8) a) Please notice that the runner must cover the trail in less time and percentage time must be negative. If we know that C = 70 and r = - 10, then his new fastest time is:

C' = 70 · (1 - 10 / 100)

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C'' = 63 · (1 - 10 / 100)

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The height after the first increase is 1.375 meters and after the second increase is 1.54 meters.

To learn more on percentages: brainly.com/question/13450942

#SPJ1

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