Answer:
the building is thirty feet tall
Step-by-step explanation:
so make a ratio of shadow to joey
5:45
simplify that to
1:9
so you can now divide 270 by nine
30
the building is thirty feet tall
10% of 140 is 14 so just add 14 to 140
140+14=154.
<em>h</em><em>i</em><em> </em><em>I am interested for your answers but I can't find 5x-3 in my profile as my number and I am currently in my second week and simplify days of my contract for my current role </em>
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If I am understanding the question correctly, farmers make up .02% (rounded to the nearest hundredth, full answer is .0192307) of the population. I calculated this by dividing 5,000,000 by 260,000,000. I then moved my decimal over 2 places to the right to convert it to a percent.
At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide