Answer:
Δ MLP ~ Δ HKG
By S-A-S similarity Postulate.
Step-by-step explanation:
Given:
In Δ MLP
MP = 20 ,
LP = 15
∠ P = 42°
In Δ HKG
HG = 16 ,
KG = 12
∠G = 42°
To Prove:
Δ MLP ~Δ HKG
Proof:
In Δ MLP and Δ HKG
..........( 1 )
..............( 2 )
∴ ...From 1 and 2
∠P ≅ ∠ G = 42° ...............Given
∴ Δ MLP ~Δ HKG ......{ By S-A-S similarity test}............Proved
