<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title=" \sqrt{x} " alt=" \sqrt{x} " align="absmiddle" c

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Zigmanuir [339]

3 years ago

lass="latex-formula"> (x-16) =?

Mathematics

2 answers:

kirill115 [55]3 years ago

7 0

We can write sqrt(x) as x^(1/2)
So we distribute the sqrt(x):
x(x^1/2)-16sqrt(x)
When multiplying like terms with powers, we add the powers. So x(x^1/2)=x^3/2
So the answer is x^3/2 -16sqrt(x)

weqwewe [10]3 years ago

3 0

√х(х-16) = х√х - 16√х

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2 years ago

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almond37 [142]

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3 years ago

In ΔNOP, the measure of ∠P=90°, the measure of ∠N=59°, and PN = 7.4 feet. Find the length of OP to the nearest tenth of a foot.

lina2011 [118]

Answer:

12.3 feet.

Step-by-step explanation:

As we are given that $\triangle NOP$ is an right angled triangle.

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And we have to find out the value of side OP to the nearest tenth of a foot by rounding off the value as seen in the attached figure as well.

By using Trigonometric functions in a right angled $\triangle$ , we know that:

$tan \theta = \frac{Perpendicular}{Base}$

Here, $\theta$ is $\angle N$ , Perpendicular is side OP and Base is side PN.

So, $tan 59^\circ = \frac{OP}{PN}$

$\Rightarrow OP = PN \times tan59^\circ$

Putting the values of PN and $tan59^\circ$ .

$OP = 1.66 \times 7.4\\\Rightarrow OP = 12.3 ft$

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2 years ago

The preimeter of the rectangle is 154 feet.The length of the rectangle is 55 feet.What is the width of the rectangle.

Alja [10]

Answer:

Step-by-step explanation:

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Alex73 [517]

Answer:

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Step-by-step explanation:

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2 years ago

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