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2 years ago

Standard deviation measures _ risk while beta measures _ risk.

Mathematics

1 answer:

Stolb23 [73]2 years ago

3 0

Answer:

Standard deviation measures Total risk while beta measures Systematic risk.

Step-by-step explanation:

The total risk is the total variability of the portfolio and includes the systematic risk and the unique risk.

The systematic risk is measured by the beta coefficient and it considers the no diversified risk such as changes in the global market. Unique risks are the ones that result from factors specifically related to the company.

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Solve each equation y-6.72=253

diamong [38]

You just need to have the variable by itself, so move the -6.72 to the other side (that will make it +6.72)
So you should have this equation now: y = 253+6.72
Then just add them and you have this: y = 259.72
And that is your answer!

Hope I helped! <3

7 0

3 years ago

Read 2 more answers

What are the factors of -20 that have a sum of -1

qaws [65]

Answer:

The factors of -20 are:

1, 2, 4, 5, 10, 20

-1, -2, -4, -5, -10, -20

Step-by-step explanation:

6 0

2 years ago

An explanation would be appreciated! Will mark BRAINLIEST for best answer! #3

Bad White [126]

Answer:8:24

Step-by-step explanation:

So since it is 1:3 and 2 dozen is 24 so 24 divided by 3 = 8 so now it’s 8:24

5 0

3 years ago

Which function describes this graph a. y=(x+5)(x-4) b. y=(x-3)(x-6) c. y=x^2-2x+4 d. y=x^2*9x+18

lara [203]

Answer:

I believe that the answer is B

6 0

2 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

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3 years ago

Standard deviation measures _____ risk while beta measures _____ risk.

Standard deviation measures _ risk while beta measures _ risk.