In order to prove the triangle is a right angled triangle we need to prove that the slope of the lines CA and BC and AB have any negative reciprocals.Lets find the slopes .
AB=(-1,3), (1,2) slope of AB = 2-3/1-(-1)= -1/2 slope of AB is -1/2
BC = (1,2), (-3,1) slope of BC is 1-2/-3-1= -1/-4 slope of BC is 1/4
Slope of CA =(-3,1)(-1,3) slope of 3-1/-1-(-3)=-2/-2=1
Since the slopes do not have any negative reciprocals so the triangle is not a right angled triangle
Answer:
16
Step-by-step explanation:
10 · 4 = 40
640/40= 16
Answer:
x(x-5)(x-8)
or
x=5
x=8
Step-by-step explanation:
- x(x^2-13x+40)
- x(x-5) (x-8)
G(h(0)) = 20
h(x) = x+4
h(0) = 0+4
h(0) = 4
g(x) = 5x
g(h(0)) = g(4) = 5(4) = 20
Answer:
-56
Step-by-step explanation:
Formula to get determinant is::
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)-8(7)
0 - 56
-56
