Explanation:
For antisense gene therapy, chemically engineered oligonucleotides complementary to specific mRNA are inserted into the cells which stop the translation of the specific protein. Similarly, the antisense drug contains the vital molecule—“the noncoding mRNA”—which blocks the translation of a specific protein.
I don't know if this will help but I did a little research and found this-
"A fundamental understanding of the different components of soil organic matter is required to best use it to improve farming systems. Total organic carbon forms are derived from the decomposition of plants and animals. They are capable of decay or are the product of decay..."
The correct answer is C. Prevention of eating disorders involves weighing often.
Explanation:
Eating disorders include multiple disorders that involve unhealthy eating habits as well as thoughts and emotions related to them. Individuals who suffer from these disorders constantly worry about their weight and appearance or have an unhealthy relationship with food, for example, individuals with anorexia or bulimia tend to believe they are "fat" even if they had low weight.
Due to this, weighing often is not a way of preventing eating disorders as this behavior just supports an unhealthy obsession with weight and appearance that can lead to eating disorders, instead, a balanced diet should be promoted and risk factors such as depression, anxiety, low self-esteem, etc should be addressed. Thus, the false statement is "Prevention of eating disorders involves weighing often".
Answer:
The correct answer is - A. Growth 1, Synthesis, Growth 2.
Explanation:
The cell cycle has three important phases Interphase, M -phase and cytokinesis. Interphase is the laongest phase of eukaryotic cell cycle. This phase shows no observational change in the cell, however, it collects nutrients, generates protein and replicates DNA and prepare the cell for the M- phase.
Interphase has 3 phases G1, S, and G2 phase. G1 phase is the phase that collects nutrients and increase the size of the cell for the cell division. S phase or synthesis phase is the phase takes maximum time in cell divivon and acompanied by protein generation, duplication of the genetic material. G2 phase is preparatory phase that prepeare the cell before the cell enter in the M - phase.
Answer: mother: XX^aa, father: X^YAa, son: X^YAa, daughter: X^X^aa.
Explanation:
Color blindness is a genetic disorder that affects the ability to distinguish colors. It is hereditary and is transmitted by an X-linked recessive allele. If a male inherits an X chromosome with the altered allele he will be color blind. In contrast, females, who have two X chromosomes, will only be colorblind if both of their X chromosomes have the altered allele. This is because <u>males have one X chromosome and one Y chromosome, while females have two X chromosomes</u>.
If the woman has normal vision, that means she cannot have both chromosomes affected. She can only have one affected chromosome (be a carrier) or none at all. Also, if she has blue eyes, which is a recessive trait, then both alleles are recessive. But the eye color is not on the X chromosome. For example, her eye color genotype can only be aa, because if she had at least one dominant allele she would have brown eye color. As for the other trait, she can be XX^, with X^ being an affected (carrier) allele or XX, i.e. both normal. So in summary, her genotype can be XXaa or XX^aa
If she has a brown-eyed male child who is also colour blind, he has inherited the allele for colour blindness from his mother, since the father does not pass on an X chromosome to the male children, only the Y. With this we can now rule out the mother's XXaa genotype since she had to have passed on her affected X^ chromosome. Then the genotype of the mother is XX^aa. And since her mother can only pass on one allele to (recessive) because she does not have allele A, the dominant that determines her brown eye color can only come from the father. So the genotype of this son is X^YAa. The female daughter has color blindness and blue eyes. So she had to inherit the affected X^ chromosome from the mother (which we already know she has) and an affected X^ chromosome from the father, because the daughter needs to inherit both affected X^ chromosomes to develop the disease. And if she also has blue eyes, she had to have inherited a recessive allele from the mother and another from the father. So with this information we can say that the father's genotype can only be X^YAa. Because the father must have both A and A alleles of the same eye color, because he passed the dominant one to the son and the recessive one to the daughter. At last, the genotype of the daughter is X^X^aa.
