B: A mutation in one of G5W's parents, during gamete formation, created an X-linked dominant disease allele.
You need to analyze the sex gametes.
Boys are XY
Girls are XX
If you have an X-linked dominant disease you need only one affected X gamete to have the disease.
The mother has XX' where X' is de affected and reproduce with a healthy man XY and breed unhealthy boys, but because of the heterozygous gametes you could also have healthy ones XX and XY
Answer:
A. 2
Explanation:
I was wrong the first time, I wasn't thinking of jupiter for some reason. sorry!
Answer:
See the answer below
Explanation:
For each heterozygous parent with the genotype BbRr, the possible gametes are: BR, Br, bR, and br. A set of these gametes from one of the parents will be lined up along the top of the Punnet's square while another set from the other parent will be lined up along the side of the square.
The result is shown in the attached image.
B They use up food and water and end up killing native species
They are both renewable resources