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Oksi-84 [34.3K]
3 years ago
11

Astronomers classify stars according to their brightness by assigning them a stellar “magnitude.” The higher the magnitude the d

immer the star. The dimmest stars visible to the naked eye have stellar magnitudes of 6. The table below shows the relative brightness of different stellar magnitudes.

Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

(a) b=100(0.4)^{m-1}

(b) The relative brightness for a stellar magnitude of 9 is <u>0.07.</u>

Step-by-step explanation:

Let the relative brightness be given by 'b' and stellar magnitude by 'm'.

(a)

Given:

The magnitude of relative brightness decreases as the magnitude of stellar increases.

From the table, we can conclude that the ratio for any two consecutive values of 'b' is the same and is equal to 0.4.

\frac{40}{100}=\frac{16}{40}=\frac{6.3}{16}=\frac{2.5}{6.3}=\frac{1}{2.5}=0.4

Now, we know that, for a common ratio 'r' of a given series, the series is called a geometric series.

The n^{th} term of a geometric series is given:

a_n=a_1r^{n-1}

Now, for the given table,m=n, b=a_n , r=0.4, a_1=100

Therefore, the equation that gives the relative brightness in terms of stellar magnitude is given as:

b=100(0.4)^{m-1}

(b)

Given:

The stellar magnitude is, m=9

The equation to find relative brightness is:

b=100(0.4)^{m-1}

Plug in 9 for 'm' and solve for 'b'. This gives,

b=100(0.4)^{9-1}\\b=0.07

Therefore, the relative brightness for a stellar magnitude of 9 is 0.07.

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<h3>How to solve the linear equation?</h3>

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