Answer:
The value of x when f(x) equals 6 is 3/5.
Step-by-step explanation:
In order to solve this problem, we shall start by inputting what we know.
Since the problem provides you with the value of f(x), we will input the value in the given equation.
Original Equation: f(x) = 5x + 3
New Equation: 6 = 5x + 3
Now that all known values of variables have been added to the equation, we will begin to solve.
Start by subtracting both sides of the equation by 3. This step is necessary to isolate x in order to find it's value.
6 = 5x + 3
6 - 3 = 5x + 3 - 3
3 = 5x
Next, we shall divide both side of the equation by 5. This step will allow us to isolate x and finally solve its value.
3 = 5x
3/5 = 5x/5
3/5 = x
Thus, the value of x in f(x) = 5x + 3 is 3/5.
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To be sure your answer is correct, insert the values of both f(x) and x into the equation provided and solve like so...
f(x) = 5x + 3
6 = 5(3/5) + 3
6 = 3 + 3
6 = 6 ✅
Answer:
244 cm³
Step-by-step explanation:
Step 1: Given data
Height of the prism with a pentagonal base (h): 8 cm
Area of the pentagonal base (A): 30.5 cm²
Step 2: Calculate the volume of the prism with a pentagonal base
We have a regular pentagonal prism, that is, the 5 sides of the base are equal and we know the area of the base and the height of the prism. We can calculate its volume using the following expression.
V = A × h
V = 30.5 cm² × 8 cm = 244 cm³
Answer:
W = 2747,1 [J]
Step-by-step explanation:
Chain is 64 meters long with mass 24 Kg
Then weight of the chain is p = 24 * 9.8
p = 235.2 [N] N = kg*m/s²
And by meter is 235,2 / 64 = 3.675
Total work has two component
- work to lift the 13 top meters of chain W₁
W₁ = ∫₀ᵇ F(y) dy
- work to lift last ( 64 - 13 ) meters 51 W₂
W₂ = 3.675 * 51 * 13 Kg m² /s² [J]
W₂ = 2436,53 [J]
We need to calculate W₁
W₁ = ∫¹³₀ mgy dy ⇒ W₁ = ∫¹³₀ 3,675 ydy
W₁ = 3,675* ∫¹³₀ ydy W₁ = 3,675* y²/2 |₀¹³
W₁ = 3,675* 84,5 [J]
W₁ = 310,54 [J]
And total work W
W = W₁ + W₂
W = 310,54 + 2436,53 [J]
W = 2747,1 [J]
Answer:3.08e
Step-by-step explanation:mujwjwieekedkd
S.A = (2×area of base) + area of lateral faces
Area of lateral faces = area of base × height
Area of lateral faces = 19×4×8=608
S.A = (2×19×4)+608
=760