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Mama L [17]
3 years ago
10

What is the length of segment AC?

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

10 units

Step-by-step explanation:

To find the length we can use the formula

d = sqrt( (y2-y1)^2 + (x2-x1)^2)

We have the two points (-5,5) and (3,-1)

d = sqrt( (-1-5)^2 + (3--5)^2)

d = sqrt( (-6)^2 + (3+5)^2)

d = sqrt( (-6)^2 + (8)^2)

d = sqrt( 36 + 64)

d = sqrt(100)

d = 10

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26 ÷ -6<br><br>as a mixed number and simplified ​
Fed [463]

Answer:

-4 1/3

Step-by-step explanation:

26 ÷ -6

= 26 / -6    (divide both top and bottom by 2)

=  13 / 3

= -13 / 3

= -4 1/3

7 0
3 years ago
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Find the value of x.
Serjik [45]

Answer:

x=30

Step-by-step explanation:

a straight line is 180 degrees so to figure out x you would do 180-151 which equals 29 however if u plug 29 in for x it wouldn't work because (29-1) equals 28 and 151+28 do not equal to 180 degrees so x would equal 30 because (30-1) is 29

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2 years ago
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What are the vertex, focus, and directrix of the parabola with the equation x2+8x+4y+4=0
Novay_Z [31]
<span>x2 +8x +4y +4 = 0
</span>4y=<span> -x2 -8x -4</span>y = -.25*x^2 -2x -1
a = -.25b = -2c = -1
x position of vertex:
h = -b / 2a
h = 2 / 2*-.25h = 2 / -.5h = -4
y position of vertex:
k = ah^2 + bh + ck = -.25*-4^2 + -2*-4 + -1k = -4 +8 -1k = 3
VERTEX = (-4, 3)**************************************************************************
x value of focus =x value of vertex = -4
y value of focus =(1 (-b^2 -4ac)) / 4a

a = -.25 b = -2 c =-1
y value = (1 (-4 -4*-.25*-1)) / 4*-.25
y value = (1 (-4 -4*-.25*-1)) / -1
y value = (1 -4 +1) / -1y value = (-2 / -1)y value = 2
focus value = (-4, 2)
Answer is the last one.

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3 years ago
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exis [7]

Answer:

where is the question ??

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How many different values can an algebraic expression like 5+(x+2)
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